Key points about the sine rule
The sine rule is a A fact, rule, or principle that is expressed in terms of mathematical symbols. The plural of formula is formulae. used to find a missing side or angle in a triangle when one pair of opposite sides and angle is given, and one other side or angle is known.
The sine rule can be expressed in two forms:
Find an unknown side using
\(\frac{π}{sinπ΄} \) = \(\frac{π}{sinπ΅} \) = \(\frac{π}{sinπΆ } \)Find an unknown angle using
\(\frac{sinπ΄}{π} \) = \(\frac{sinπ΅}{π} \) = \(\frac{sinπΆ }{π} \)
Scientific calculators need to be used for trigonometry and should be in degrees mode. Often there is a small D or DEG at the top of the calculator screen. If not, go into the calculator settings to change the angle units to degrees.
To be successful with non-right-angled A branch of mathematics which explores the relationships between sides and angles in a triangle., make sure you are confident in finding unknown sides and angles in right-angled triangles.
How to find an unknown side using the sine rule
To use the sine rule to find an unknown side, one pair of opposite side and angle must be known. For example, angle π΄ and side π. The angle opposite the unknown side must also be known.
Label the angles and side of the triangle and use the formula \(\frac{π}{sinπ΄} \) = \(\frac{π}{sinπ΅} \) = \(\frac{π}{sinπΆ } \) to find the missing side.
The sine rule involves three equal ratios, but any calculation only requires two of the three parts.
If the vertices of the triangle are not called π΄, π΅ and πΆ, it is common practice to rename them to assist with the The process of replacing a letter (or variable) with a number. into the formula.
Follow the worked example below
GCSE exam-style questions
- Calculate the length of side π¦.
Give the answer to one decimal place.
π¦ = 8Β·4 cm
- Label the sides of the triangle.
The 8 cm side, opposite angle π΄, is called π.
The side labelled π¦, opposite angle πΆ is called π and the unknown side, opposite angle π΅, is called π.
Since neither side π nor angle π΅ is known, this is the portion of the sine rule formula that will not be used.
Substitute the values of π΄, πΆ, π and π into the formula to give
\(\frac{8}{sin(60)} \) = \(\frac{π¦}{sin(66)} \)Rearrange the equation to make π¦ the subject.
Find the value of π¦ by multiplying both sides of the equation by sin(66).
This gives \(\frac{8sin(60)}{sin(60)} \) = π¦.
- Type \(\frac{8sin(60)}{sin(60)} \) into a scientific calculator.
Usually, the calculator will automatically open a bracket after pressing the sin button.
Remember to close the bracket each time after typing in the angle.
This gives π¦ = 8Β·4389β¦
Rounded to 1 decimal place, π¦ = 8Β·4 cm.
- Calculate the length of side π₯.
Give the answer to one decimal place.
π₯ = 3Β·5 m
- Label the sides of the triangle.
The 11 m side, opposite angle πΆ, is called π.
The side labelled π₯, opposite angle π΅, is called π and the unknown side, opposite angle π΄, is called π.
- To use the sine rule, the angle opposite π₯ must be calculated.
The angles in a triangle add up to 180Β°.
180 β 96 β 68 = 17
Angle π΅ = 17Β°.
Substitute the values of π΅, πΆ, π and π into the formula to give
\(\frac{π₯}{sin(17)} \) = \(\frac{11}{sin(68)} \)Rearrange the equation to make π₯ the subject.
Find the value of π₯ by multiplying both sides of the equation by sin(17).
This gives π₯ = \(\frac{11sin(17)}{sin(68)} \).
- Type 11sin(17) Γ· sin(68) into a scientific calculator.
This gives π₯ = 3Β·4686β¦
Rounded to 1 decimal place, π₯ = 3Β·5 m.
- Calculate the length of side ππ.
Give the answer to one decimal place.
ππ = 8Β·9 cm
1.Label the sides of the triangle.
Since the vertices are not called π΄,π΅ and πΆ, let vertex π be π΄, π be π΅ and π be πΆ.
The 4 cm side, opposite angle π΅, is called π.
The side ππ (or π΄π΅), opposite angle πΆ, is called π and the unknown side, opposite angle π΄ is called π.
Since neither side π nor angle π΄ is known, this is the portion of the sine rule formula that will not be used.
Substitute the values of π΅, πΆ, π and π into the formula to give
\(\frac{4}{sin(21)} \) = \(\frac{ππ}{sin(127)} \)Rearrange the equation to make ππ the subject.
Multiply both sides of the equation by sin(127) to find the value of ππ.
This gives \(\frac{4sin(127)}{sin(21)} \) = ππ.
- Type 4sin(127) Γ· sin(21) into a scientific calculator.
This gives ππ = 8Β·9141β¦
The length of ππ, rounded to 1 decimal place, = 8Β·9 cm.
How to find an unknown angle using the sine rule
To use the sine rule to find an unknown angle, an angle and its opposite side must be known. For example, angle π΄ and side π.
The length of the side opposite the unknown angle must also be known.
Label the angles and sides of the triangle and use the formula
\(\frac{sinπ΄}{π} \) = \(\frac{sinπ΅}{π} \) = \(\frac{sinπΆ }{π} \) to find the missing angle.
As with the previous application of the sine rule, only two parts of the formula will be used in the calculation.
Remember, when finding angles using trigonometry the The opposite of a mathematical process. trigonometric functions are used.
Follow the worked example below
GCSE exam-style questions
- Calculate the size of angle π΄.
Give the answer to one decimal place.
π΄ = 32Β·5Β°
- Label the sides of the triangle.
The 9 m sides, opposite angle πΆ, is called π.
The 5 m side, opposite angle π΄, is called π, and the unknown side, opposite angle π΅ is called π.
Since neither side π, nor angle π΅ is known, this is the portion of the sine rule formula that will not be used.
Substitute the values of π΄, πΆ, π and π into the formula to give\(\frac{sinπ΄}{5} \) = \(\frac{sin(75)}{9} \).
Rearrange the equation to make sinπ΄ the subject.
Multiply both sides of the equation by 5 to find the value of sinπ΄. This gives sinπ΄ = \(\frac{5sin(75)}{9} \).
- Type 5sin(75) Γ· 9 into a scientific calculator.
This is the value of sinπ΄.
This gives sinπ΄ = 0Β·5366β¦
It is important not to round the number at this stage.
- Calculate angle π΄, using the inverse function of sine.
π΄ = sinβ»ΒΉ(0Β·5366β¦)
Press 'Shift' then 'sin' to write sinβ»ΒΉ on a scientific calculator.
- Next, use the 'ANS' button which will substitute the value of the previous decimal.
This gives π΄ = 32Β·4542β¦
Rounded to 1 decimal place, π΄ = 32Β·5Β°.
- Calculate the size of angle πππ.
Give the answer to one decimal place.
Angle πππ = 24Β·8Β°
- Label the sides of the triangle.
Since the vertices are not called π΄,π΅ and πΆ, let vertex π be π΄, π be π΅ and π be πΆ.
The 3 cm side, opposite angle πΆ, is called π.
The 7 cm side, opposite angle π΄, is called π, and the unknown side, opposite angle π΅, is called π.
Since neither side π nor angle π΅ is known, this is the portion of the sine rule formula that will not be used.
Substitute the values of π, π, π₯ and π§ into the formula to give \(\frac{sin(78)}{7} = \frac{sinπ}{3} \).
Rearrange the equation to make sinπ the subject.
Multiply both sides of the equation by 3 to find the value of sinπ.
This gives \(\frac{3sin(78)}{7} = sinπ\).
- Type 3sin(78) Γ· 7 into a scientific calculator.
This is the value of sinπ.
This gives sinπ = 0Β·4192β¦
It is important not to round the number at this stage.
- Calculate angle π, using the inverse function of sine.
π = sinβ»ΒΉ (0Β·4192β¦).
Press 'Shift' then 'sin' to write sinβ»ΒΉ on a scientific calculator.
- Next, use the 'ANS' button which will substitute the value of the previous decimal.
Remember to close the brackets.
This gives π = 24Β·7844β¦
Rounded to 1 decimal place, angle πππ = 24Β·8Β°.
Check your understanding
Finding an unknown angle using the sine rule: the ambiguous case
When calculating an angle using the sine rule, sometimes there are two possible answers.
This is called the ambiguous case.
Find one answer, as before, using the formula
\(\frac{sinπ΄}{π} \) = \(\frac{sinπ΅}{π} \) = \(\frac{sinπΆ }{π} \).
The second answer is found by subtracting the first answer from 180Β°.
If the angles in the triangle do not exceed the angle sum of a triangle, 180Β°, the second answer can exist.
Follow the worked example below
GCSE exam-style questions
- Triangle π΄π΅πΆ has sides π΄πΆ = 7 m, π΄π΅ = 8 m and
angle π΅ = 55Β°.
Angle πΆ is obtuse.
Find the size of angle πΆ.
Give the answer to one decimal place.
πΆ = 110Β·6Β°
- Label the sides of the triangle.
The 8 m side, opposite angle πΆ, is called π.
The 7 m side, opposite angle π΅, is called π, and the unknown side, opposite angle π΄, is called π.
Since neither side π nor angle π΄ is known, this is the portion of the sine rule formula that will not be used.
Substitute the values of π΅, πΆ, π and π into the formula to give \(\frac{sin(55)}{7} \) = \(\frac{sinπΆ}{8} \)
Rearrange the equation to make sinπΆ the subject.
Find the value of sinπΆ by multiplying both sides of the equation by 5.
This gives \(\frac{8sin(55)}{7} \) = sinπΆ.
- Type 8sin(55) Γ· 7 into a scientific calculator.
This is the value of sinπΆ.
This gives sinπΆ = 0Β·9361β¦
It is important not to round the number at this stage.
- Work out angle, πΆ, using the inverse function of sine.
πΆ = sinβ»ΒΉ (0Β·9361β¦)
Press 'Shift' then 'sin' to write sinβ»ΒΉ on a scientific calculator.
- Next use the βANSβ button which will substitute the value of the previous decimal. Remember to close the brackets.
This gives πΆ = 69Β·4186β¦
Rounded to 1 decimal place, πΆ = 69Β·4Β°.
- This answer is acute so cannot be the required answer.
Use the graph of π¦ = sin(π₯) to find the second answer.
The graph shows there is another angle which satisfies sinπΆ = 0Β·9361β¦
Since the graph is symmetrical, the second answer is found by subtracting the first answer from 180Β°.
180 β 69Β·4186β¦ = 110Β·5814β¦
Angle πΆ equals 110Β·6Β°, which is an obtuse angle.
- Triangle πππ has side ππ = 9 cm, ππ = 6 cm and angle π = 35Β°.
Work out the two possible values for angle π.
Give the answers to one decimal place.
π = 59Β·4Β° and 120Β·6Β°
- Label the sides of the triangle.
Since the vertices are not called π΄, π΅ and πΆ, let vertex π be π΄, π be π΅ and π be πΆ.
The 6 m side, opposite angle π, is called π₯.
The 9 m side, opposite angle π, is called π§, and the unknown side, opposite angle π, is called π¦.
Since neither side π¦ nor angle π is known, this is the portion of the sine rule formula that will not be used.
Substitute the values of π, π, π₯ and π§ into the formula to give \(\frac{sin(35)}{6} = \frac{sinπ}{9} \).
Rearrange the equation to make sinπ the subject.
Find the value of sinπΆ by multiplying both sides of the equation by 5.
This gives \(\frac{9sin(35)}{6} \) = sinπ.
- Type 9sin(35) Γ· 6 into a scientific calculator.
This is the value of sinπ.
This gives sinπ = 0Β·8603β¦
It is important not to round the number at this stage.
- Work out angle, π, using the inverse function of sine.
π = sinβ»ΒΉ (0Β·8603β¦)
Press 'Shift' then 'sin' to write sinβ»ΒΉ on a scientific calculator.
6, Next use the βANSβ button which will substitute the value of the previous decimal. Remember to close the brackets.
This gives π = 59Β·3575β¦
Rounded to 1 decimal place, π = 59Β·4Β°.
- Use the graph of π¦ = sin(π₯) to find the second answer.
The graph shows there is another angle which satisfies sinπ = 0Β·8603β¦
Since the graph is symmetrical, the second answer is found by subtracting the first answer from 180Β°.
180 β 59Β·3575 = 120Β·6425
Angle π can also be equal to 120Β·6Β°.
Quiz β Sine rule
Practise what you've learned about the sine rule with this quiz.
Now you've revised the sine rule, why not look at Calculating angles using circles?
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